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Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決
Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決
數與式計算
Jul 2nd 2013, 12:47

998^3+4*999+998*997-999*998*997

=998*(998*998-999*997)+4*999+998*997

=998*[998*998 - (998+1)*(998-1)]+4*999+998*997

=998*[998^2 - 998^2 + 1^2]+4*(1000-1)+(1000-2)*(1000-3)

=998 + 4000 -4 + 1000000 -2000 - 3000 + 6

=1000000

1000000開3次方根號 = 100

答:100

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