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有關F.2 畢氏定理問題詢問
Jun 2nd 2013, 11:11

議一直角三角形三條邊的長度,其中它們均為無理數。

開方2, 開方15, 開方17
因為3^2 + 4^2 = 5^2
所以(3π)^2 + (4π)^2 = (5π)^2
有理數x無理數=無理數
π 是無理數,所以直角三角形三條邊 3π, 4π , 5π均為無理數

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